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AD8200 Arkusz danych(PDF) 7 Page - Analog Devices

Numer części AD8200
Szczegółowy opis  High Common-Mode Voltage, Single-Supply Difference Amplifier
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Producent  AD [Analog Devices]
Strona internetowa  http://www.analog.com
Logo AD - Analog Devices

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REV. B
AD8200
–7–
Internal Signal Overload Considerations
When configuring gain for values other than 20, the maximum
input voltage with respect to the supply voltage and ground
must be considered, since either the preamplifier or the output
buffer will reach its full-scale output (approximately VS – 0.2 V)
with large differential input voltages. The input of the AD8200
is limited to (VS – 0.2)
÷ 10, for overall gains ≤10, since the
preamplifier, with its fixed gain of
×10, reaches its full-scale
output before the output buffer. For gains greater than 10, the
swing at the buffer output reaches its full scale first and limits
the AD8200 input to (VS – 0.2)
÷ G, where G is the overall gain.
LOW-PASS FILTERING
In many transducer applications, it is necessary to filter the
signal to remove spurious high frequency components, including
noise, or to extract the mean value of a fluctuating signal with a
peak-to-average ratio (PAR) greater than unity. For example, a
full-wave rectified sinusoid has a PAR of 1.57, a raised cosine
has a PAR of 2, and a half-wave sinusoid has a PAR of 3.14.
Signals having large spikes may have PARs of 10 or more.
When implementing a filter, the PAR should be considered so
the output of the AD8200 preamplifier (A1) does not clip before
A2, since this nonlinearity would be averaged and appear as an
error at the output. To avoid this error, both amplifiers should
be made to clip at the same time. This condition is achieved
when the PAR is no greater than the gain of the second ampli-
fier (2 for the default configuration). For example, if a PAR of 5
is expected, the gain of A2 should be increased to 5.
Low-pass filters can be implemented in several ways using the
features provided by the AD8200. In the simplest case, a single-
pole filter (20 dB/decade) is formed when the output of A1 is
connected to the input of A2 via the internal 100 k
Ω resistor by
strapping Pins 3 and 4 and a capacitor added from this node to
ground, as shown in Figure 8. If a resistor is added across the
capacitor to lower the gain, the corner frequency will increase; it
should be calculated using the parallel sum of the resistor and
100 k
Ω.
5V
C
VCM
OUT
FC =
1
2 C105
C IN FARADS
VDIFF
2
VDIFF
2
NC = NO CONNECT
GND
NC
–IN
+IN
A1
+VS
A2
OUT
AD8200
Figure 8. A Single-Pole, Low-Pass Filter Using the
Internal 100 k
Ω Resistor
If the gain is raised using a resistor, as shown in Figure 8, the
corner frequency is lowered by the same factor as the gain is
raised. Thus, using a resistor of 200 k
Ω (for which the gain
would be doubled), the corner frequency is now 0.796 Hz-
µF,
(0.039
µF for a 20 Hz corner frequency.)
OUT
VCM
C
255k
C
FC = 1Hz – F
5V
NC = NO CONNECT
VDIFF
2
VDIFF
2
GND
NC
–IN
+IN
A1
+VS
A2
OUT
AD8200
Figure 9. 2-Pole Low-Pass Filter
A 2-pole filter (with a roll-off of 40 dB/decade) can be implemented
using the connections shown in Figure 9. This is a Sallen-Key
form based on a
×2 amplifier. It is useful to remember that a 2-pole
filter with a corner frequency f2 and a 1-pole filter with a corner
at f1 have the same attenuation at the frequency (f2
2/f
1). The
attenuation at that frequency is 40 log (f2/f1). This is illustrated
in Figure 10. Using the standard resistor value shown and equal
capacitors (Figure 9), the corner frequency is conveniently scaled at
1 Hz-
µF (0.05 µF for a 20 Hz corner). A maximally flat response
occurs when the resistor is lowered to 196 k
Ω and the scaling is
then 1.145 Hz-
µF. The output offset is raised by approximately
5 mV (equivalent to 250 V at the input pins).
40LOG (f2/f1)
f1
f2
f2
2/f
1
FREQUENCY
A 1-POLE FILTER, CORNER f1, AND
A 2-POLE FILTER, CORNER f2, HAVE
THE SAME ATTENUATION –40LOG (f2/f1)
AT FREQUENCY f2
2/f
1
20dB/DECADE
40dB/DECADE
Figure 10. Comparative Responses of 1-Pole and
2-Pole Low-Pass Filters


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